| 步骤 | 例子 (无附带校验码的商品代码) | ||||||||||||
6 | 2 | 9 | 1 | 0 | 4 | 1 | 5 | 0 | 0 | 2 | 1 | A | |
| 步驟一:自左向右编号 | N13 | N12 | N11 | N10 | N9 | N8 | N7 | N6 | N5 | N4 | N3 | N2 | N1 |
| 步驟二:计算偶数编号对应的数的和的3倍数B | (2+1+4+5+0+1) x 3 = 39 | ||||||||||||
| 步驟三:奇数编号对应的商品代码数的和C | 6+9+0+1+0+2 = 18 | ||||||||||||
| 步驟四:计算B+C的总数D | 39 + 18 = 57 | ||||||||||||
| 步驟五:10减以总数D的个位数 = 校验码A求出校验码A | 10-7 = 3 | ||||||||||||
| 附带校验码的商品代码 | 6 | 2 | 9 | 1 | 0 | 4 | 1 | 5 | 0 | 0 | 2 | 1 | 3 |
| 步骤 | 例子 (无附带校验码的商品代码) | ||||||||||||
| 6 | 2 | 9 | 1 | 0 | 4 | 1 | 5 | 0 | 0 | 2 | 1 | A | |
| 步驟一:自右向左编号 | N1 | N2 | N3 | N4 | N5 | N6 | N7 | N8 | N9 | N10 | N11 | N12 | N13 |
| 步驟二:乘以每一位置相应的的数目 (N奇数 x 1, N偶数 x 3) | x1 | x3 | x1 | x3 | x1 | x3 | x1 | x3 | x1 | x3 | x1 | x3 | |
| 6 | 6 | 9 | 3 | 0 | 12 | 1 | 15 | 0 | 0 | 2 | 3 | | |
| 步驟三:求出步驟二得出的数值的总数C | C = 6+6+9+3+0+12+1+15+0+0+2+3 = 57 | ||||||||||||
| 步驟三:10减以总数C的个位数 = 校验码A | A = 10 – 7 = 3 | ||||||||||||
| 附带校验码的商品代码 | 6 | 2 | 9 | 1 | 0 | 4 | 1 | 5 | 0 | 0 | 2 | 1 | 3 |
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